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0.9X^2-8X-544=0
a = 0.9; b = -8; c = -544;
Δ = b2-4ac
Δ = -82-4·0.9·(-544)
Δ = 2022.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-\sqrt{2022.4}}{2*0.9}=\frac{8-\sqrt{2022.4}}{1.8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+\sqrt{2022.4}}{2*0.9}=\frac{8+\sqrt{2022.4}}{1.8} $
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